- Sun Jan 20, 2013 12:00 am
#41234
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=4995)
The correct answer choice is (C)
If J leads the Thursday afternoon session, then L must lead the Thursday morning session since J and L are paired together on the same day. From the second and fourth rules, the NO block must lead sessions on Friday, with N leading the afternoon session (from the third rule) and O leading the morning session. That leaves the KR block to lead the Wednesday sessions, but the specific assistant leading the morning and afternoon sessions cannot be determined.
Combining this information leads to the following setup:
Thus, four of the assistants are assigned to specific sessions. However, the answer to this problem is not four. Instead, the question stem assigns J, and then asks for “how many of the other lab assistants” can be determined (italics added for emphasis). Thus, the correct answer is three, and answer choice (C) is correct.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=4995)
The correct answer choice is (C)
If J leads the Thursday afternoon session, then L must lead the Thursday morning session since J and L are paired together on the same day. From the second and fourth rules, the NO block must lead sessions on Friday, with N leading the afternoon session (from the third rule) and O leading the morning session. That leaves the KR block to lead the Wednesday sessions, but the specific assistant leading the morning and afternoon sessions cannot be determined.
Combining this information leads to the following setup:
Thus, four of the assistants are assigned to specific sessions. However, the answer to this problem is not four. Instead, the question stem assigns J, and then asks for “how many of the other lab assistants” can be determined (italics added for emphasis). Thus, the correct answer is three, and answer choice (C) is correct.
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