Hi Sara,
This is a really difficult drill (by design), and it's the kind of drill that really makes you stop and consider how what conditional statements mean, how uncertainty works, and what must, can, and cannot occur under specific statements.
The first thing to realize is that the reasoning being used here is a type that we use every single day. You are actually very familiar with conditional reasoning, but what you aren't familiar with is the kind of cold, clinical usage of conditionality that you see on the LSAT and in this drill. If I changed these drills around to use the names of your friends and family (for example, "if Adam comes to the party then Bjorn comes to the party too (A
B); what must, could, and cannot occur if Bjorn comes to the party?" you'd probably feel much more comfortable with this drill
Second, the Could and Cannot parts giving you trouble is pretty normal. But the fact that the Must questions didn't bother you is a good sign—it means that at this point you understand what the immediate consequences are of each conditional statement when you are given a second piece of information. Getting that part down means that understanding the Could and Cannot parts is simply a matter of seeing the rest of the picture. Part of that is simple adjustment. You get asked about what Must occur so frequently in LSAT prep that you get used to that quickly; Could and Cannot questions in this form come up much less, so that unfamiliarity is a big part of the problem.
That said, let's take a look about how to think about a drill like this, by using the first question in #1 as a template. The diagram there is: A
B
C, and the question posed is what happens when B does not occur (
B )?
I tend to mentally organize it as a set of options for each variable. I know immediately that there are three variables—A, B, and
C. But what also exist are their opposites—
A,
B, and C. So, I'm looking at all this knowing that the different outcomes will revolve around those six basic possibilities.
We know from the question that B does not occur. B appears in the middle of the chain, and so what are the immediate results? Well, the diagram features B, and the question features
B, so the condition in the diagram isn't met. That means that for C (which is is "downstream" as
C), that anything can happen. Either C could occur or it can not occur; we simply don't know. Hence, on the Could Be True line we'll have both C and
C.
Going back to
B, we know that is the opposite of B, and so this means that the necessary condition in A
B has not occurred, enacting a contrapositive. Consequently, we know that A does not occur (
A ), and thus that is added to the Must Be True line. Well, if
A occurs, then the opposite
cannot occur, meaning that A cannot occur, and that is added to the Cannot Be True line. At that point, we've looked at all the options for A and C, and that means we're done.
That's the same process I use for each of the problems—examine each variable and it's opposite (such as C and
C), and consider the range of what's forced to occur and not occur.
Also, I previously wrote out an explanation for #2 that you might find useful:
http://forum.powerscore.com/lsat/viewto ... =28&t=3763
Please let me know if that helps. Thanks!