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General questions relating to LSAT Logical Reasoning.
 akanshalsat
  • Posts: 104
  • Joined: Dec 20, 2017
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#49042
Hello!

I just have a few questions with some of the drill questions on page 435

for number 5, I know that the diagram is: I :most: J :dbl: K :arrow: L
-The inference that they went from J to L being: J :arrow: L, why wasn't it J :dbl: L?
B/c if it had been written J :some: K :arrow: L, we would have retained the :some: and have written: J :some: L

For number 3, I know the diagram is E :dblline: F :arrow: G :arrow: H

why can't we also infer E :dblline: G and E :dblline: H?
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 Jonathan Evans
PowerScore Staff
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#49063
Hi, Akan,

Great questions!
for number 5, I know that the diagram is: I :most: J :dbl: K :arrow: L
-The inference that they went from J to L being: J :arrow: L, why wasn't it J :dbl: L?
B/c if it had been written J :some: K :arrow: L, we would have retained the :some: and have written: J :some: L
The reason is because :some: and :dbl: have different implications.

:some: implies that there is overlap between two groups. For example:
  • "Some dogs are pets."
    Dogs :some: Pets
    Pets :some: Dogs
Now lets add a conditional statement into the mix.
  • "All dogs are mammals."
    Dogs :arrow: Mammals
We know that there is overlaps between pets and mammals:
  • Pets :some: Mammals
In contrast :dbl: is a material equivalence, a bidirectional conditional. It implies that two sets are equivalent to each other. For example:
  • "Someone is a college graduate if and only if he or she has been awarded an undergraduate degree from an academic institution."

    UD :dbl: CG
However, if you connect a one-directional conditional to this bidirectional conditional, it remains one-directional:
  • "All college graduates must repay their student loans.

    CG :arrow: RSL
The implication is still UD :arrow: Student loans. We do not know that everyone who must repay his or her student loans is also a recipient of an undergraduate degree (*RSL :arrow: UD). Thus, we cannot infer *UD :dbl: RSL.
For number 3, I know the diagram is E :dblline: F :arrow: G :arrow: H

why can't we also infer E :dblline: G and E :dblline: H?
This situation is similar to the one discussed above. One-directional conditional statements do not imply their converse. In other words, we don't want to make a Mistaken Reversal™ error. Here's an example:
  • "No cats are dogs."

    C :dblline: D

    "All dogs are mammals."

    D :arrow: M
It does not follow that "no cats are mammals." We cannot infer *C :dblline: M.

Does this make sense? Thanks for the good questions!

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