- Thu Jan 11, 2024 2:28 pm
#104846
Correct! We already know from one of the rules that G and H cannot be in Group O, and since another rule tells us that G and M must be together, that means M also cannot be in Group O. That leaves F, K, and L, three of our original six, who might be able to go there.
The only other thing to do now if to ask ourselves whether something would prevent any one of them from being in that group, and to do that it would help to look back at answers to previous questions. The first question proved that K could be in that group, so there's one of our three. In question 8, we saw L was forced to be in Group O, so that's two so far. And the real kicker is question 9, where we had to have more in Group O than in Group R, which already had to have more than Group V. That gave us a 3-2-1 fixed distribution, and we for sure had to have all of F, K, and L in Group O since nobody else could be there! Prior work is a great source for answering questions like this one quickly, confidently, and accurately.
Adam M. Tyson
PowerScore LSAT, GRE, ACT and SAT Instructor
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