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- Thu Mar 01, 2018 6:17 pm
#44159
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=13729)
The correct answer choice is (B)
From the basic physical constraints of the game, Philadelphia can only connect with four other cities: Honolulu, Montreal, Toronto, and Vancouver. From the fourth rule, we know that Philadelphia cannot connect to both Toronto and Vancouver, and thus, the options for Philadelphia are H, M, and V/T. The question stem in #12 indicates that exactly three cities are connected with Philadelphia. Hence, we know we are selecting from the group of H, M, and V/T. But, because of the action of the third rule, when Philadelphia is connected with Honolulu, then Philadelphia must also be connected with Toronto. We can then determine in question #12 that Philadelphia is connected only to H, M, and T, as follows:
Because P cannot connect with V, we can eliminate answer choice (E). Also, because M is now connected to P, from the second rule we know that M cannot connect with any other city. Thus, answer choices (A), (C), and (D) can be eliminated. Therefore, answer choice (B) is proven correct by process of elimination.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=13729)
The correct answer choice is (B)
From the basic physical constraints of the game, Philadelphia can only connect with four other cities: Honolulu, Montreal, Toronto, and Vancouver. From the fourth rule, we know that Philadelphia cannot connect to both Toronto and Vancouver, and thus, the options for Philadelphia are H, M, and V/T. The question stem in #12 indicates that exactly three cities are connected with Philadelphia. Hence, we know we are selecting from the group of H, M, and V/T. But, because of the action of the third rule, when Philadelphia is connected with Honolulu, then Philadelphia must also be connected with Toronto. We can then determine in question #12 that Philadelphia is connected only to H, M, and T, as follows:
Because P cannot connect with V, we can eliminate answer choice (E). Also, because M is now connected to P, from the second rule we know that M cannot connect with any other city. Thus, answer choices (A), (C), and (D) can be eliminated. Therefore, answer choice (B) is proven correct by process of elimination.
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Dave Killoran
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
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PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/