LSAT and Law School Admissions Forum

Get expert LSAT preparation and law school admissions advice from PowerScore Test Preparation.

User avatar
 Dave Killoran
PowerScore Staff
  • PowerScore Staff
  • Posts: 5862
  • Joined: Mar 25, 2011
|
#89134
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?f=246&t=32245)

The correct answer choice is (D)

If S was born before Z, then Z must have been born in 1994, as in Template #2:

G3-Q13-d1.png

Consequently, answer choice (D) is proven correct. Also, please note that in this template, the E in the 1990 child row forces a corresponding E in the L/R row, and in turn you can infer that in 1995 a right-handed child was born.
You do not have the required permissions to view the files attached to this post.
User avatar
 cgmcali
  • Posts: 1
  • Joined: Jan 02, 2024
|
#104649
I am struggling to find a pattern that would allow me to have Sarah born before Zoe, but also have someone born in 1990. In other words, I am wondering why Answer Choice: E is incorrect.

If Sarah is born before Zoe, and Sarah is in 1991, who could be born in 1990? It can't be Zoe, because she was born after Sarah. It can't be Uma, because they are born in 1993. It can't be Theo or Will because they must come after Zoe, meaning they can never be in a first spot.

Where am I going wrong in my logic? Thanks
 Adam Tyson
PowerScore Staff
  • PowerScore Staff
  • Posts: 5191
  • Joined: Apr 14, 2011
|
#104658
Your logic is correct, cgmcali: no child can be born in 1990 in this scenario. That's why answer E must be true, which makes it a wrong answer to this Cannot Be True question. Don't lose track of the question stem! They are asking for the one answer that cannot happen, and answer E is something that must happen, the polar opposite of what we want!

Get the most out of your LSAT Prep Plus subscription.

Analyze and track your performance with our Testing and Analytics Package.