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 KathrynJ
  • Posts: 8
  • Joined: Jan 29, 2012
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#3514
Hello,

I apologize if this is addressed elsewhere, but if it takes me anywhere near 8 min 45 sec to find something, I'm starting a new topic!

In the answer explanantion, it says that O is not possible at table 4. Could someone please explain why?

Thanks!
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 Dave Killoran
PowerScore Staff
  • PowerScore Staff
  • Posts: 5993
  • Joined: Mar 25, 2011
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#3518
Hey Kathryn,

Sure, glad to help! Here is the explanation:

The “O” Not Law on table 4 is correct because placing O on 4 causes a violation of the third rule:

When O is placed at table 4, then tables 1, 2, and 3 must be occupied by patrons P, Q, and M (not necessarily in that order). This forces the Empty table (variable “E”) to be assigned to table 5, 6, or 7. Unfortunately, that assignment is a violation of the third rule that states that tables 5, 6, and 7 must be occupied by a patron.

Please let me know if that helps. Thanks!
 KathrynJ
  • Posts: 8
  • Joined: Jan 29, 2012
|
#3558
Yep, that helps! Tricky! Gotta train in these types of things!

Thanks.

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