#10 - Local, Could Be True, Except

[Dave Killoran]

Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=1171)

The correct answer choice is (C)

If no two cars have exactly the same options, then Z must have S because W already has L and P. In addition, T cannot have S because Y already has just S. This information leads to the following setup:

Oct 01_M12_game#2_L9_explanations_game#1_#10_diagram_1.png

Because four of the cars already have S, answer choice (C) cannot be true and is correct.

[stsai]

Hi David,

Thanks for the reply. I see that I missed the "Z must have L" part, and that solves #9.
But how do I solve #10?
Seems to me I could refer to the template used for #9:
T-P, V-PS, W-PL, X-PLS, Y-S, Z-LS
(also the only possibility if no two cars were to have exactly the same options with one another, I assume)

Then this would make (A) (C) (E) all selectable as cannot be true (reverse of could be true X, right?)

[Dave Killoran]

Hi Stsai,

On #10, I think your error is coming from the assumption that T-P, V-PS, W-PL, X-PLS, Y-S, Z-LS is the only viable hypothetical. Remember, since Y has S only, T can have P or L, this solution also applies to this problem:

T-L, V-PS, W-PL, X-PLS, Y-S, Z-LS

This solution shows that answer choices (A) and (E) are possible, and thus they are incorrect.

Please let me know if that solves this problem. Thanks!

[stsai]

Yes. That was the problem. Now I get it. Thanks!