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- Sat May 05, 2018 12:28 pm
#45466
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=4080)
The correct answer choice is (D)
If there are two hamsters in W then there must be two gerbils in W as well (to make an even number of animals). That means the last gerbil must be in X, leaving just one gerbil in cage X. According to the question stem, if there is one gerbil in X, then there is only one snake in Y, and the four remaining snakes must be in Z. Thus, answer choice (D) is correct.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=4080)
The correct answer choice is (D)
If there are two hamsters in W then there must be two gerbils in W as well (to make an even number of animals). That means the last gerbil must be in X, leaving just one gerbil in cage X. According to the question stem, if there is one gerbil in X, then there is only one snake in Y, and the four remaining snakes must be in Z. Thus, answer choice (D) is correct.
Dave Killoran
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
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PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/