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- Mon Jan 20, 2014 12:00 am
#79280
Setup and Rule Diagram Explanation
This is a Mapping—Supplied Diagram, Identify the Possibilities game.
This game might seem somewhat intimidating, but in reality it is just an exercise in connecting the dots. While at first there may appear to be a large number of solutions, two factors combine to limit the number of solutions to six total: the limited number of segments, and the limited ways those segments can connect the chalets. Let’s examine both factors in more detail.
There are only five total segments (or paths) that must be shown. Because two of the five line segments are already given (J-N and K-L), only three more remain to be drawn. With only three segments left, there are a limited number of possible combinations of those segments.
The three segments are also limited in the way they can be drawn because of the rule that disallows the paths to cross, and the rule that maximizes the number of connections to a chalet to two. Those two rules further reduce the number of possible solutions, and should suggest to you that one way to solve this game would be to Identify the Possibilities.
Let’s look at the initial setup to the game:
The first thing that should be apparent to you is that M is limited in the chalets it can connect to. Because of the actions of the first and fourth rules, M cannot connect to K, L, or O. Thus, M must be directly connected to either J or N, but it cannot be connected to both or that would be a violation of the third rule. At the same time, from the second rule M must connect to another chalet, so M must be connected to J, or M must be connected to N, but not both. This limitation is one of the keys to the game.
With the that limitation in mind, let’s examine the various solutions to the game:
Scenario Set 1: J and M connected
When J and M are connected, three segments are used, and two remain to be placed:
In this configuration, M is now “closed” to further connections, as is J (J is connected to two other chalets, and thus from the third rule J can not connect to any more chalets). Thus, only K, L, N, and O are available to connect the remaining two segments. From here, only four possible connections exist: K-N, L-O, N-O, and K-O. Any viable solution will use exactly two of these connections, so examine those possibilities and make sure they meet the rules.
1. K-N connections
When K and N are connected, N and K are then closed off to further connection (from the third rule), and so the only remaining possible connection is L-O:
2. L-O connections
When L and O are connected, L is then closed off to further connection (from the third rule), and so the only remaining possible connection is K-N (which we just covered above) or N-O:
3. N-O connections
When N and O are connected, N is then closed off to further connection (from the third rule), and so the only remaining possible connection is L-O (which we just covered above) or K-O:
4. K-O connections
When K and O are connected, K is then closed off to further connection (from the third rule), and so the only remaining possible connection is N-O, which was in the prior discussion.
Let’s now examine the next set of possibilities, the ones that occur when M and N are connected.
Scenario Set 2: M and N connected
When M and N are connected, three segments are used, and two remain to be placed:
In this configuration, M is now “closed” to further connections, as is N (N is connected to two other chalets, and thus from the third rule N can not connect to any more chalets). Thus, only J, K, L, and O are available to connect the remaining two segments. From here, only four possible connections exist: J-K, J-O, L-O, and K-O. Any viable solution will use exactly two of these connections, so examine those possibilities and make sure they meet the rules.
1. J-K connections
When J and K are connected, J and K are then closed off to further connection (from the third rule), and so the only remaining possible connection is L-O:
2. J-O connections
When J and O are connected, J is then closed off to further connection (from the third rule), and so the only remaining possible connection is K-O or L-O:
J-O and K-O
J-O and L-O
3. L-O connections
When L and O are connected, L is then closed off to further connection (from the third rule), and so the only remaining possible connection is J-O, which we just covered above. K-O is not a viable connection because then all six chalets would not be connected in a single, continuous path as specified in the scenario.
4. K-O connections
When K and O are connected, K is then closed off to further connection (from the third rule), and so the only remaining possible connection is J-O, which was covered in an earlier discussion.
So, there are only six possible solutions to the game:
This is a Mapping—Supplied Diagram, Identify the Possibilities game.
This game might seem somewhat intimidating, but in reality it is just an exercise in connecting the dots. While at first there may appear to be a large number of solutions, two factors combine to limit the number of solutions to six total: the limited number of segments, and the limited ways those segments can connect the chalets. Let’s examine both factors in more detail.
There are only five total segments (or paths) that must be shown. Because two of the five line segments are already given (J-N and K-L), only three more remain to be drawn. With only three segments left, there are a limited number of possible combinations of those segments.
The three segments are also limited in the way they can be drawn because of the rule that disallows the paths to cross, and the rule that maximizes the number of connections to a chalet to two. Those two rules further reduce the number of possible solutions, and should suggest to you that one way to solve this game would be to Identify the Possibilities.
Let’s look at the initial setup to the game:
The first thing that should be apparent to you is that M is limited in the chalets it can connect to. Because of the actions of the first and fourth rules, M cannot connect to K, L, or O. Thus, M must be directly connected to either J or N, but it cannot be connected to both or that would be a violation of the third rule. At the same time, from the second rule M must connect to another chalet, so M must be connected to J, or M must be connected to N, but not both. This limitation is one of the keys to the game.
With the that limitation in mind, let’s examine the various solutions to the game:
Scenario Set 1: J and M connected
When J and M are connected, three segments are used, and two remain to be placed:
In this configuration, M is now “closed” to further connections, as is J (J is connected to two other chalets, and thus from the third rule J can not connect to any more chalets). Thus, only K, L, N, and O are available to connect the remaining two segments. From here, only four possible connections exist: K-N, L-O, N-O, and K-O. Any viable solution will use exactly two of these connections, so examine those possibilities and make sure they meet the rules.
1. K-N connections
When K and N are connected, N and K are then closed off to further connection (from the third rule), and so the only remaining possible connection is L-O:
2. L-O connections
When L and O are connected, L is then closed off to further connection (from the third rule), and so the only remaining possible connection is K-N (which we just covered above) or N-O:
3. N-O connections
When N and O are connected, N is then closed off to further connection (from the third rule), and so the only remaining possible connection is L-O (which we just covered above) or K-O:
4. K-O connections
When K and O are connected, K is then closed off to further connection (from the third rule), and so the only remaining possible connection is N-O, which was in the prior discussion.
Let’s now examine the next set of possibilities, the ones that occur when M and N are connected.
Scenario Set 2: M and N connected
When M and N are connected, three segments are used, and two remain to be placed:
In this configuration, M is now “closed” to further connections, as is N (N is connected to two other chalets, and thus from the third rule N can not connect to any more chalets). Thus, only J, K, L, and O are available to connect the remaining two segments. From here, only four possible connections exist: J-K, J-O, L-O, and K-O. Any viable solution will use exactly two of these connections, so examine those possibilities and make sure they meet the rules.
1. J-K connections
When J and K are connected, J and K are then closed off to further connection (from the third rule), and so the only remaining possible connection is L-O:
2. J-O connections
When J and O are connected, J is then closed off to further connection (from the third rule), and so the only remaining possible connection is K-O or L-O:
J-O and K-O
J-O and L-O
3. L-O connections
When L and O are connected, L is then closed off to further connection (from the third rule), and so the only remaining possible connection is J-O, which we just covered above. K-O is not a viable connection because then all six chalets would not be connected in a single, continuous path as specified in the scenario.
4. K-O connections
When K and O are connected, K is then closed off to further connection (from the third rule), and so the only remaining possible connection is J-O, which was covered in an earlier discussion.
So, there are only six possible solutions to the game:
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Dave Killoran
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/