I'll give it a try, lsatdaynnight!
First, Rule 2 tells us that if G is before T, then R and S must also be before T. I won't be able to draw that in this forum exactly as I would on paper, but it's basically this:
G
T
R and S
T
When you do the contrapositive, you reverse the order and change the "and" that is in the necessary condition to an "or" in the sufficient condition, so you get this:
(T
R OR T
S)
T
G
(Switching the order is "negating" the conditions here since there can be no ties. T can only be before G or else after G.)
When we build templates in this game around the last rule, we get two starting positions. Either H is before both S and T or else it is after both S and T. H can never be between them.
If we start with S and T both before H, and we couple that with the first rule that H is always before R, we get:
S and T
H
R
This triggers the contrapositive of the second rule, because T is before R. Thus, in this template, T must also be before G. Either S or T is first, and G could be second (after T) or as late as last.
In the other template, with H before R, S, and T, we don't know where T falls in that order, so we can split it into two sub-templates, one in which G is before T (forcing T to be last, because it must also be after both R and S), and one in which T is before G, in which case the order of T relative to R and S is completely undetermined and therefore entirely flexible. In that case, T could be as early as second (because it must still be after H) and as late as fourth (because it must be before G). It could also fall in the third spot, between R and S in either order.
Draw that all out and you will have three templates that cover every possible solution to the game!
Adam M. Tyson
PowerScore LSAT, GRE, ACT and SAT Instructor
Follow me on Twitter at
https://twitter.com/LSATadam