- Thu Jul 13, 2017 11:49 pm
#37277
Question 22 is a Could Be True with the Local condition that I's second visit is to T. What might that mean?
I visiting S and T may not seem to tell us much, but if you're focused on numbers and the fact that we've used our two Is then we know more than you might suspect. Take our completely open city, M. We now have G, F, and H to fill those two spots. However, since we can't have F and H fill them, we know G must take a spot on M!
And of course as soon as G goes to M then H must go to T, which fills T: H and I are there.
We still have to place at least one F, and this is where the inferences dry up, but still...not bad:
? ? H
G I I
M S T
Since it's a Could Be True question I'm focused on those two ?s that I've shown, looking for an answer that deals with those elements of uncertainty.
And it doesn't take long: answer choice (A) is correct, since G and F could both visit M. That's allowed by the diagram above, and would still give options for the second S visit (either H or F could fill that spot).
The other answers are all impossible:
Answer choice (B): I goes to S and T, so this is out.
Answer choice (C): I goes to S and T, so this too is out.
Answer choice (D): T is filled by H and I, so no room for F. This is out.
Answer choice (E): Even if H is our double, one of H's visits is to T, so this answer is out (would lead to three H visits).
Not too bad...
I visiting S and T may not seem to tell us much, but if you're focused on numbers and the fact that we've used our two Is then we know more than you might suspect. Take our completely open city, M. We now have G, F, and H to fill those two spots. However, since we can't have F and H fill them, we know G must take a spot on M!
And of course as soon as G goes to M then H must go to T, which fills T: H and I are there.
We still have to place at least one F, and this is where the inferences dry up, but still...not bad:
? ? H
G I I
M S T
Since it's a Could Be True question I'm focused on those two ?s that I've shown, looking for an answer that deals with those elements of uncertainty.
And it doesn't take long: answer choice (A) is correct, since G and F could both visit M. That's allowed by the diagram above, and would still give options for the second S visit (either H or F could fill that spot).
The other answers are all impossible:
Answer choice (B): I goes to S and T, so this is out.
Answer choice (C): I goes to S and T, so this too is out.
Answer choice (D): T is filled by H and I, so no room for F. This is out.
Answer choice (E): Even if H is our double, one of H's visits is to T, so this answer is out (would lead to three H visits).
Not too bad...
Jon Denning
PowerScore Test Preparation
Follow me on Twitter at https://twitter.com/jonmdenning
My LSAT Articles: http://blog.powerscore.com/lsat/author/jon-denning
PowerScore Test Preparation
Follow me on Twitter at https://twitter.com/jonmdenning
My LSAT Articles: http://blog.powerscore.com/lsat/author/jon-denning