- PowerScore Staff
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- Joined: Feb 02, 2011
- Mon Nov 06, 2017 4:55 pm
#41255
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=6505)
The correct answer choice is (A)
The question stem is posed in terms of falsity, and you should immediately convert that into terms of true. Thus, this question actually asks for what Cannot Be True.
Each of the answer choices places two representatives in a particular zone. Because the rules are relatively straightforward in this game, the correct answer is likely to violate the Numerical Distribution. Thus, examine each answer choice with an eye on the numerical requirements for each zone.
Answer choice (A) cannot occur and is the correct answer. S can only work in Zone 1 under Template #2. In that template, P and Q already work in Zone 1. Because U must work in the same zone as S, there are then four workers in Zone 1: P, Q, S, and U. Thus, if K is added to Zone 1, five workers work in Zone 1, and one representative works in each of the other zones. This distribution violates the fourth rule, and thus, K and S cannot work together in Zone 1.
Answer choice (B) is incorrect because K and S could both work in Zone 3 under Template #2.
Answer choice (C) is incorrect because M and S could both work in Zone 3 under Template #2. Because both K and M are randoms, and thus operate in a similar fashion, this answer is functionally identical to answer choice (B). In any LSAT question, two answers that are functionally identical are both incorrect.
Answer choice (D) is incorrect because M and U could both work in Zone 3 under Template #2. Note that this answer is functionally identical to answer choice (C) because S and U operate in an identical fashion.
Answer choice (E) is incorrect because P and S could both work in Zone 1 under Template #2.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=6505)
The correct answer choice is (A)
The question stem is posed in terms of falsity, and you should immediately convert that into terms of true. Thus, this question actually asks for what Cannot Be True.
Each of the answer choices places two representatives in a particular zone. Because the rules are relatively straightforward in this game, the correct answer is likely to violate the Numerical Distribution. Thus, examine each answer choice with an eye on the numerical requirements for each zone.
Answer choice (A) cannot occur and is the correct answer. S can only work in Zone 1 under Template #2. In that template, P and Q already work in Zone 1. Because U must work in the same zone as S, there are then four workers in Zone 1: P, Q, S, and U. Thus, if K is added to Zone 1, five workers work in Zone 1, and one representative works in each of the other zones. This distribution violates the fourth rule, and thus, K and S cannot work together in Zone 1.
Answer choice (B) is incorrect because K and S could both work in Zone 3 under Template #2.
Answer choice (C) is incorrect because M and S could both work in Zone 3 under Template #2. Because both K and M are randoms, and thus operate in a similar fashion, this answer is functionally identical to answer choice (B). In any LSAT question, two answers that are functionally identical are both incorrect.
Answer choice (D) is incorrect because M and U could both work in Zone 3 under Template #2. Note that this answer is functionally identical to answer choice (C) because S and U operate in an identical fashion.
Answer choice (E) is incorrect because P and S could both work in Zone 1 under Template #2.