Hi, Kelly!
This game benefits from two basic templates:
PT83 Dec 2017 Game 3 Setup.png
Notice that R, N, and L are all connected to each other. Let's explore a couple possibilities. As you mention, if N is open, so is L. Then R is closed. I used this for the first template. I stipulated that in this scenario we do not know where P, Q, or M go. These three are our randoms in this template.
In the second scenario, I've put R into the open group instead of N. R open means M is also open. R open means that L is closed. L closed means that N is also closed. In this second template, only P and Q are randoms.
For question #16, we are asked which station must close if exactly two stay open. Either one of our templates would work in this scenario. The breakdown would be as follows:
- Question # 16
Template 1 Open: N L, Closed: R P Q M
Template 2 Open: R M, Closed: N L P Q
In both scenarios, both P and Q must be closed. Therefore, the correct answer will be P or Q. That's how we get the correct answer, (D).
For question #17, you don't really need the templates. What you have to do is try to replicate the effect of the substituted rule. The original rule is:
- R M
We need to make a replacement rule that would have the same result. In other words, we need to make R open sufficient to guarantee M open. Let's ask ourselves what else R open does. We can look for any other R open sufficient condition. There is one other R open sufficient condition:
- R L
Since R open also means L closed, we can make a chain conditional to replicate the original rule. We do this by making L closed the new sufficient condition to guarantee M open:
- L M
Now altogether we have a new chain conditional:
- R L M
The implication is that if R is open, M is open too. This is identical to the original rule.
I hope this helps!
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