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- Thu Mar 01, 2018 6:15 pm
#44157
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=13729)
The correct answer choice is (A)
In this Global question it is useful to note that each answer choice is given in the same form. In each answer choice, a pair of cities is given and the question is whether the pair can only be connected to each other, and not to any other city. Because any city connected with Honolulu must also be connected with Toronto, attempting to connect Toronto with only one other city is not feasible. For example, as in answer choice (B), if Montreal and Toronto are only connected to each other, there will be a violation because any city then connected to Honolulu will have to be connected to Toronto. Using this line of reasoning, we can eliminate each of the answers that contains Toronto, namely answer choices (B), (C), and (E).
Answer choice (D) is tricky, but when Philadelphia and Vancouver are only connected to each other, the result is that no other city is available to connect to Honolulu, a violation of the game scenario. As indicated in our discussion of the third rule, we know that neither M nor T can connect to H. Thus, H must be connected to at least P or V. However, in answer choice (D) neither of those two cities is available to H. Hence, answer choice (D) cannot occur and is incorrect. Therefore, answer choice (A) is correct.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=13729)
The correct answer choice is (A)
In this Global question it is useful to note that each answer choice is given in the same form. In each answer choice, a pair of cities is given and the question is whether the pair can only be connected to each other, and not to any other city. Because any city connected with Honolulu must also be connected with Toronto, attempting to connect Toronto with only one other city is not feasible. For example, as in answer choice (B), if Montreal and Toronto are only connected to each other, there will be a violation because any city then connected to Honolulu will have to be connected to Toronto. Using this line of reasoning, we can eliminate each of the answers that contains Toronto, namely answer choices (B), (C), and (E).
Answer choice (D) is tricky, but when Philadelphia and Vancouver are only connected to each other, the result is that no other city is available to connect to Honolulu, a violation of the game scenario. As indicated in our discussion of the third rule, we know that neither M nor T can connect to H. Thus, H must be connected to at least P or V. However, in answer choice (D) neither of those two cities is available to H. Hence, answer choice (D) cannot occur and is incorrect. Therefore, answer choice (A) is correct.
Dave Killoran
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
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PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/