LSAT 2017 edition Page 117

[T9909]

I am confused with the answer for question 12.2.

I understand that 3-1-1-1-1-1-1 does not necessarily mean 3 must be scheduled on the first day, and the same goes for:
2-2-1-1-1-1-1, and again 2 does not need to be in the first two slots. My question is, why couldn't the answer choice be B? It states the maximum number must be 2. Since three is free to move wherever, couldn't we apply the second distribution 2-2-1-1-1-1-1 to this question and; therefore, B is our answer?

As I write my question out, is it because 3 can be a maximum in any slot (aside from Wednesday) and the answer choices presented to us limit us? Although, 2 can move around, in the end 3 is always going to be the maximum in this distribution?

[Jonathan Evans]

Hey T9909,

I think you've got it! Yes, since there can be three on Tuesday, it is not true that the maximum number of patients scheduled for Tuesday is two. There could possibly be three patients scheduled for Tuesday. Remember, this is a "Must Be True" question. We have to find an answer that describes a condition that must always be true. While it could be true that there are two patients scheduled for Tuesday, this does not have to be true. There could be three on Tuesday.

Please follow up with further questions!