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- Fri Jan 21, 2011 12:00 am
#26961
Setup and Rule Diagram Explanation
This is an Advanced Linear Game: Unbalanced: Underfunded.
This game is Underfunded because there are only seven variables for nine spaces. Since each traveler can be assigned to only one seat, it follows that two seats will be empty. In order to more gracefully handle this empty space, you should create an “E” or “X” variable to indicate the empty space (in this case we chose X). This maneuver transforms the game from Unbalanced: Underfunded to Balanced. X is then treated like any other variable.
Note carefully that the third rule states that R’s seat is the row behind the row in which N’s seat is located. The rule does not say that R’s seat is the seat behind N’s seat. This rule is often misinterpreted by test takers. Remember, always read closely!
Because the RPX block must be in the row behind N, and O is already in the last row, we can infer that the RPX will be in the middle row. Consequently, N must be in the front row.
At this point, from an abstract standpoint, the first three rules are well under control, or dead. The only active rule is the last rule, and you should be expect to be tested on the application of this rule. This last rule produces several Not Laws and inferences:
This is an Advanced Linear Game: Unbalanced: Underfunded.
This game is Underfunded because there are only seven variables for nine spaces. Since each traveler can be assigned to only one seat, it follows that two seats will be empty. In order to more gracefully handle this empty space, you should create an “E” or “X” variable to indicate the empty space (in this case we chose X). This maneuver transforms the game from Unbalanced: Underfunded to Balanced. X is then treated like any other variable.
Note carefully that the third rule states that R’s seat is the row behind the row in which N’s seat is located. The rule does not say that R’s seat is the seat behind N’s seat. This rule is often misinterpreted by test takers. Remember, always read closely!
Because the RPX block must be in the row behind N, and O is already in the last row, we can infer that the RPX will be in the middle row. Consequently, N must be in the front row.
At this point, from an abstract standpoint, the first three rules are well under control, or dead. The only active rule is the last rule, and you should be expect to be tested on the application of this rule. This last rule produces several Not Laws and inferences:
- Because N must be assigned to the front row, at least one of S and U must be assigned to the last row, and neither S nor U can be assigned seat 2.
If N is assigned seat 2, then both S and U must be assigned to the last row.
If S and U is assigned seat 1 or 3, then N must be assigned to the seat at the other end of the row.
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Dave Killoran
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
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PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/