- Tue Jan 21, 2020 12:00 am
#75198
Setup and Rule Diagram Explanation
This is a Defined (Moving) Grouping game, with a significant distributional component. It's also a game in which there is some real value to using the Identify the Templates technique.
A few notes on the setup and templates:
1. The rule involving P and S functions to create a block in this game. This is because each variable must be used exactly once. Thus, in the one group where P is assigned, S must also be present. And there is nowhere else S can be assigned (since it can only be used once).
2. Since all 6 textbooks are edited exactly once, but we only know that each editor edits "at least one" of the textbooks, we have uncertainty about the distribution of the 3 remaining textbooks. The setup further fixes the distribution by assigning H exactly two textbooks to edit. Since F and G each must edit at least one textbook, there are only two possible general distributions of the remaining 4 textbooks to those two, a 3-1, or a 2-2.
3. It's worth sketching out each general distributional option at the start. In the F=3, G=1, H=2 distribution, we don't get a lot of additional information about where the variables go, but we do know that the PS block cannot be assigned to G, who only edits one textbook in this template. Further subdividing this template into 2 options is possible, if not completely necessary: one where the PS block and L/Z are assigned to F (in which case, M will be assigned to G, and R and one of L/Z will be assigned to H); another where the PS block is assigned to H (in which case the other variables are more flexible in placement).
4. The F=1, G=3, H=2 distribution is impossible, because there is nowhere M can be assigned. It can never be assigned to H. It can only be assigned to G if it is the only textbook assigned to G. And it cannot be assigned to F, because F must edit at least L or Z. Templating is thus very valuable because it exposes the impossibility of this distribution.
5. The F=2, G=2, H=2 distribution is relatively detailed. M must be assigned to F (along with L/Z), since it cannot be assigned to G where G edits more than one textbook. There must be a group of P and S (since wherever P is assigned, S will go). And there will be another group of R with L/Z. We don't know where the PS and R-L/Z groups will be assigned but knowing they are present confers significant advantage when it comes to this distribution.
This is a Defined (Moving) Grouping game, with a significant distributional component. It's also a game in which there is some real value to using the Identify the Templates technique.
A few notes on the setup and templates:
1. The rule involving P and S functions to create a block in this game. This is because each variable must be used exactly once. Thus, in the one group where P is assigned, S must also be present. And there is nowhere else S can be assigned (since it can only be used once).
2. Since all 6 textbooks are edited exactly once, but we only know that each editor edits "at least one" of the textbooks, we have uncertainty about the distribution of the 3 remaining textbooks. The setup further fixes the distribution by assigning H exactly two textbooks to edit. Since F and G each must edit at least one textbook, there are only two possible general distributions of the remaining 4 textbooks to those two, a 3-1, or a 2-2.
3. It's worth sketching out each general distributional option at the start. In the F=3, G=1, H=2 distribution, we don't get a lot of additional information about where the variables go, but we do know that the PS block cannot be assigned to G, who only edits one textbook in this template. Further subdividing this template into 2 options is possible, if not completely necessary: one where the PS block and L/Z are assigned to F (in which case, M will be assigned to G, and R and one of L/Z will be assigned to H); another where the PS block is assigned to H (in which case the other variables are more flexible in placement).
4. The F=1, G=3, H=2 distribution is impossible, because there is nowhere M can be assigned. It can never be assigned to H. It can only be assigned to G if it is the only textbook assigned to G. And it cannot be assigned to F, because F must edit at least L or Z. Templating is thus very valuable because it exposes the impossibility of this distribution.
5. The F=2, G=2, H=2 distribution is relatively detailed. M must be assigned to F (along with L/Z), since it cannot be assigned to G where G edits more than one textbook. There must be a group of P and S (since wherever P is assigned, S will go). And there will be another group of R with L/Z. We don't know where the PS and R-L/Z groups will be assigned but knowing they are present confers significant advantage when it comes to this distribution.
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Jeremy Press
LSAT Instructor and law school admissions consultant
Follow me on Twitter at: https://twitter.com/JeremyLSAT
LSAT Instructor and law school admissions consultant
Follow me on Twitter at: https://twitter.com/JeremyLSAT