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- Thu Nov 08, 2018 3:43 pm
#60236
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=15932)
The correct answer choice is (E)
The assignment of F to the second meeting has an immediate impact on the choices for the first meeting. We know that only F, R or T could be Garibaldi’s first meeting. With F as the second meeting, the first meeting cannot be with F as that would violate the second rule. The first meeting also cannot be with T as there is no room to place S immediately after T. Consequently, when F is Garibaldi’s second meeting, R must be Garibaldi’s first meeting:
This powerful deduction immediately eliminates answer choices (A), (B), and (D), each of which contain R. A very insightful test taker might realize at this point which of the foreign dignitaries could be Garibaldi’s fourth meeting, but let’s continue analyzing this problem as if we did not have that insight.
Comparing the remaining two answer choices, (C) and (E), both contain S, so the comparison should focus on M and F, the unique variables in each of the remaining answer choices.
Answer choice (C): A quick test of this answer would be to create a hypothetical that places M into the fourth meeting:
Placing M fourth immediately forces the two remaining Fs into the fifth and seventh meetings:
At this point there is no room for the TS block, and so we can eliminate this answer choice since placing M fourth does not allow us to create a viable solution.
Answer choice (E): This is the correct answer choice. The following hypothetical proves that F can be Garibaldi’s fourth meeting:
(The complete setup for this game can be found here: lsat/viewtopic.php?t=15932)
The correct answer choice is (E)
The assignment of F to the second meeting has an immediate impact on the choices for the first meeting. We know that only F, R or T could be Garibaldi’s first meeting. With F as the second meeting, the first meeting cannot be with F as that would violate the second rule. The first meeting also cannot be with T as there is no room to place S immediately after T. Consequently, when F is Garibaldi’s second meeting, R must be Garibaldi’s first meeting:
This powerful deduction immediately eliminates answer choices (A), (B), and (D), each of which contain R. A very insightful test taker might realize at this point which of the foreign dignitaries could be Garibaldi’s fourth meeting, but let’s continue analyzing this problem as if we did not have that insight.
Comparing the remaining two answer choices, (C) and (E), both contain S, so the comparison should focus on M and F, the unique variables in each of the remaining answer choices.
Answer choice (C): A quick test of this answer would be to create a hypothetical that places M into the fourth meeting:
Placing M fourth immediately forces the two remaining Fs into the fifth and seventh meetings:
At this point there is no room for the TS block, and so we can eliminate this answer choice since placing M fourth does not allow us to create a viable solution.
Answer choice (E): This is the correct answer choice. The following hypothetical proves that F can be Garibaldi’s fourth meeting:
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Dave Killoran
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
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PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/