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- Thu Aug 30, 2018 3:09 pm
#55803
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=23743)
The correct answer choice is (B)
As briefly mentioned in the game setup, only two of the clients can possibly meet first, at 1:00. Let’s take a moment to review this inference further.
As established in the discussion of the third rule, the first three rules can be connected together to create the following chain:
From this chain we can infer that T, W, and Y can never be first since each must come after S (although, for the purposes of this question, W is irrelevant since W is not an actual client).
From the fourth rule, we can infer that R can never be first since R must always meet with Patterson after U meets with Patterson. Consequently, we have eliminated R, T, and Y from meeting with Patterson at 1:00. This leaves only S and U as clients who could possibly meet with Patterson at 1:00, and thus “two” is the correct answer.
Answer choice (A), (C), (D), and (E): As discussed above, these answer choices must be incorrect because they do not state the maximum number of clients that could meet with Patterson at 1:00.
Answer choice (B): This is the correct answer choice.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=23743)
The correct answer choice is (B)
As briefly mentioned in the game setup, only two of the clients can possibly meet first, at 1:00. Let’s take a moment to review this inference further.
As established in the discussion of the third rule, the first three rules can be connected together to create the following chain:
From this chain we can infer that T, W, and Y can never be first since each must come after S (although, for the purposes of this question, W is irrelevant since W is not an actual client).
From the fourth rule, we can infer that R can never be first since R must always meet with Patterson after U meets with Patterson. Consequently, we have eliminated R, T, and Y from meeting with Patterson at 1:00. This leaves only S and U as clients who could possibly meet with Patterson at 1:00, and thus “two” is the correct answer.
Answer choice (A), (C), (D), and (E): As discussed above, these answer choices must be incorrect because they do not state the maximum number of clients that could meet with Patterson at 1:00.
Answer choice (B): This is the correct answer choice.
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Dave Killoran
PowerScore Test Preparation
Follow me on Twitter at http://twitter.com/DaveKilloran
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PowerScore Test Preparation
Follow me on Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore PodCast: http://www.powerscore.com/lsat/podcast/