#2 - Global, Must Be True

[Dave Killoran]

Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=23743)

The correct answer choice is (B)

As briefly mentioned in the game setup, only two of the clients can possibly meet first, at 1:00. Let’s take a moment to review this inference further.

As established in the discussion of the third rule, the first three rules can be connected together to create the following chain:

pt45_d04_g1_q2.png

From this chain we can infer that T, W, and Y can never be first since each must come after S (although, for the purposes of this question, W is irrelevant since W is not an actual client).

From the fourth rule, we can infer that R can never be first since R must always meet with Patterson after U meets with Patterson. Consequently, we have eliminated R, T, and Y from meeting with Patterson at 1:00. This leaves only S and U as clients who could possibly meet with Patterson at 1:00, and thus “two” is the correct answer.

Answer choice (A), (C), (D), and (E): As discussed above, these answer choices must be incorrect because they do not state the maximum number of clients that could meet with Patterson at 1:00.

Answer choice (B): This is the correct answer choice.