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 Dave Killoran
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#41618
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=14535)

The correct answer is (A)

If S is on exactly two floors, then from the first rule, S must be on floors 2 and 3, and F must be on floor 1. Applying the key inferences, we can then deduce that P is on the second and third floors as well:
D91_Game_#3_#14_diagram 1.png
As this is a Could Be True question, you should immediately seek an answer that addresses the two uncertainties in the diagram: N or U on floor 2, and P or R on floor 1. Answer choice (A) addresses the uncertainty on floor 1, and is correct.
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 jbrown1104
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#46785
Hello PS!

I was wondering if you could please clarify how you got N/U on floor 2 and P/R on floor 1. My global diagram and inferences were correct, however I just want to make sure my reasoning for this question's diagram is correct.

The reason why floor 2 and floor 3 have the dual options is because you cannot predict with the inferences or their contrapositives what variable should be there. Example, because the original inference for F was R---->F if we had an R we know immediately it is F. BUT because the questions gives us F we cannot assume that R is the variable selected because that would be a Mistaken Reversal, given that the contrapositive is not F---->not R.

The same applies for floor 2 which is why the dual option N/U is present. Am I correct in my reasoning?

Thanks!
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 Jonathan Evans
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#46793
Hi, JBrown,

Excellent work. You are correct about both!

Thanks for sharing your reasoning.
 mollylynch
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#102724
How do we know the family cars on floor 1 are new?
 Adam Tyson
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#102736
That's from the original rules, Molly! The cars on the first floor are always New.

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