Setup and Rule Diagrams

[Adam Tyson]

If at least one task is done each day, sofcu23, that means there can't be a day where no work gets done (unlike every real construction project I've ever seen, where some days nothing gets done and nobody shows up to work). That's why setups like 3-0-2 or 3-2-0 are impossible. Every day there has to be something done.

Two days is possible, as long as at least one task is done on the first day and at least one task is done on the second day. Imagine, for example, that the first 4 tasks (FWTS) are all done on day 1, and the final task (P) is done on day 2. In that situation, the whole job was completed in two days, and there was something done on each of those days. There is no third day, so it's not a 3-2-0 distribution, but a 3-2 distribution!

[izsake]

Hello,

I am still struggling with this explanation - you say that "there can't be a day where no work gets done", but with a 4-1 distribution, no work is being done on the third day?

Thanks in advance!

If at least one task is done each day, sofcu23, that means there can't be a day where no work gets done (unlike every real construction project I've ever seen, where some days nothing gets done and nobody shows up to work). That's why setups like 3-0-2 or 3-2-0 are impossible. Every day there has to be something done.

Two days is possible, as long as at least one task is done on the first day and at least one task is done on the second day. Imagine, for example, that the first 4 tasks (FWTS) are all done on day 1, and the final task (P) is done on day 2. In that situation, the whole job was completed in two days, and there was something done on each of those days. There is no third day, so it's not a 3-2-0 distribution, but a 3-2 distribution!

[izsake]

Okay upon further reflection, am I understanding this right - there can be a 3-2 or 4-1 distribution because if all the work is completed by day 2, then there just isn't anything left to be completed on day 3, thus only needing 2 days? (For my own brain, neither 2-3 nor 1-4 work because T and P must be on different days).

I think I am getting so hung up on the first rule, but then in combination of "at most three days" in the premise, that initially I believed that there had to be three days worth of work.

[Adam Tyson]

You got it, izsake! If the job is done in 2 days, there is no third day on which no work gets done. What they are trying to say there is that you cannot have a 3-0-2 distribution, or a 0-3-2, or 4-0-1. If there are 3 days to the job, at least one task is done on each of the 3 days.

[t.j.dub]

I made a horribly inefficient diagram for game 3, what would the ideal one look like for this type of game?

[Stephanie Oswalt]

I made a horribly inefficient diagram for game 3, what would the ideal one look like for this type of game?

Hi t.j.,

Thanks for the post. I have moved your post to the explanation of Lesson 7 HW Game 3. Please review the official explanation here: viewtopic.php?f=288&t=8601, and let us know if you have any additional questions!