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General questions relating to the LSAT Logic Games.
 SLF
  • Posts: 40
  • Joined: Oct 01, 2013
|
#11569
Given the following...

"If it is not the case that the park contains both L and O, then it contains F and S."

Based on this, it makes sense to me that If I have neither L nor O, then I must have both F and S.

But, what if I have L but not O then must I still have both F and S?

Likewise, if I have O but not L then must I still have both F and S?

Thanks for your help.
 Ron Gore
PowerScore Staff
  • PowerScore Staff
  • Posts: 220
  • Joined: May 15, 2013
|
#11570
Hi, SLF!

Thanks for your question. You've definitely identified a tricky conditional statement. Your statement was:

"If it is not the case that the park contains both L and O, then it contains F and S."

The sufficient condition in this relationship is that the park does not contain BOTH L and O. This does not mean that both L and O are absent from the park, but rather that at least one of them is absent. So, relationship is:

..... ..... ..... L ..... ..... ..... ..... ..... ..... ..... F

..... ..... .....OR ..... ..... ..... :arrow: ..... ..... ..... AND

..... ..... ..... O ..... ..... ..... ..... ..... ..... .....S

The contrapositive of this relationship is that if either F or S is absent, then both L and O must be present.

..... ..... ..... F ..... ..... ..... ..... ..... ..... ..... L

..... ..... .....OR ..... ..... ..... :arrow: ..... ..... ..... AND

..... ..... ..... S ..... ..... ..... ..... ..... ..... .....O

I hope this helps. Please let me know if I may assist you further.

Ron
 SLF
  • Posts: 40
  • Joined: Oct 01, 2013
|
#11572
I deeply appreciate your prompt reply.

I was making the the sufficient condition an 'and' relationship and that was where I was off track.

Thank you.

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