#10 - Local, Must Be True

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Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=3673)

The correct answer choice is (D)

As with Question #9, it is best to consider the conditions in this Local questions one at a time:

If L is shown three times, it must be shown on all three days. Consequently, L must be the last
film shown on Friday (second rule), but not the last film shown on Thursday (first rule) or
Saturday (third rule). Also, G cannot be shown on Friday in compliance with the second rule:

june07_game_2_#10_diagram_1.png

Next, we are asked to show H exactly twice, and G – exactly once. We know that H must be the
last film shown on Thursday, but not whether the second showing of H would occur on Friday or
Saturday. Either seems possible, warranting the creation of two local diagrams:

If the second H is shown on Friday, then G must be shown on Saturday in compliance with the
third rule. The local condition requires only one showing of G, which is why G cannot be shown
on Thursday. Thus, the assignment of films to each of the three days is completely defined:

june07_game_2_#10_diagram_2.png

Alternatively, the second H is shown on Saturday. If so, then G cannot be shown on Saturday in
compliance with the last rule. But, G cannot be shown on Friday either, because L is the last film
shown on that day. Consequently, G must be shown on Thursday, as either the first or the second
of the three films shown that day:

june07_game_2_#10_diagram_3.png

With these two solutions in place, we can say with confidence that either G or L must the first
film shown on Thursday, proving that answer choice (D) contains a complete and accurate list of
these films.