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- Sat Dec 24, 2016 8:57 am
#88232
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?f=174&p=88228#p88228)
The correct answer choice is (A).
Answer choice (A) is correct because as shown in Template #1, W can be the sole signee of agency S (T can sign with F or P). This becomes a difficult question if you make the mistake of believing that the last rule creates a TW block. Remember, conditional rules are only active when the sufficient condition is met (or the necessary condition is not met). If T does not sign with S, then W can sign with any agency (as long as the remaining rules are met, of course).
Answer choice (B) is incorrect because assigning W, Y, and Z to P leaves only T to sign with S, which creates a violation of the last rule because W is unavailable to sign with S as well.
Answer choice (C) is incorrect because if Z signs with the same agency as X, from the third rule Y must also sign with that agency, which is a violation of the second rule.
Answer choice (D) is incorrect because if Z is the only performer to sign with S, then Y signs with a different agency, which is a violation of the third rule.
Answer choice (E) is incorrect because if three performers sign with F, those performers would have to be X, W, and T (Y and Z cannot sign with F due to the first three rules). But, this creates a violation of the numerical minimums because only Z and Y remain, and they must both be assigned to the same agency, leaving one agency with no signees.
(The complete setup for this game can be found here: lsat/viewtopic.php?f=174&p=88228#p88228)
The correct answer choice is (A).
Answer choice (A) is correct because as shown in Template #1, W can be the sole signee of agency S (T can sign with F or P). This becomes a difficult question if you make the mistake of believing that the last rule creates a TW block. Remember, conditional rules are only active when the sufficient condition is met (or the necessary condition is not met). If T does not sign with S, then W can sign with any agency (as long as the remaining rules are met, of course).
Answer choice (B) is incorrect because assigning W, Y, and Z to P leaves only T to sign with S, which creates a violation of the last rule because W is unavailable to sign with S as well.
Answer choice (C) is incorrect because if Z signs with the same agency as X, from the third rule Y must also sign with that agency, which is a violation of the second rule.
Answer choice (D) is incorrect because if Z is the only performer to sign with S, then Y signs with a different agency, which is a violation of the third rule.
Answer choice (E) is incorrect because if three performers sign with F, those performers would have to be X, W, and T (Y and Z cannot sign with F due to the first three rules). But, this creates a violation of the numerical minimums because only Z and Y remain, and they must both be assigned to the same agency, leaving one agency with no signees.
Dave Killoran
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
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PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/