Hi kristinaroz93,
Thanks for your questions! Let me briefly address each one of them individually.
1. Regarding your first question, yes - you are absolutely correct. Let me elaborate on each of the two rules whose combination yields the inference you are asking about:
1. NOT H L
(Contrapositive: NOT L H)
Notice that the sufficient condition here is negative, while the necessary condition is positive. Essentially, the rule tells us that if either H or L does
not occur, the other one
has to occur. In other words, at least one of H or L must occur. Under this rule, there are three possible outcomes:
H occurs but L does not occur
L occurs but H does not occur
both H and L occur
It is critical to recognize that this rule does not prohibit both H and L from occurring together. Just because at least one of them has to occur does not mean that both of them cannot occur at the same time.
Now, compare this rule to the rule about L and M:
2. L NOT M
Contrapositive: M NOT L
The Double-Not arrow (L
M) is a shortcut that we use to represent a relationship between two variables, wherein the sufficient condition is positive and the necessary condition is negative. The arrow captures both the original rule and its contrapositive; however, sometimes I just use the regular arrow and negate the necessary condition. It does not matter how you represent this relationship, as long as you know what it allows, and what it disallows.
Under this rule, the following outcomes are possible:
L occurs but M does not occur
M occurs but L does not occur
neither L nor M occurs
Unlike the previous rule, this one allows for the possibility that neither M nor L occurs; however, it prohibits M and L from occurring together - at least one of them does
not occur.
Note that the distinction between these two rules was also discussed by Dave Killoran on this recent blog:
http://blog.powerscore.com/lsat/the-mos ... -rule-lsat
The two rules above can be combined, and their combination yields the following conditional chain:
NOT H L NOT M
Contrapositive: M NOT L H
Shortcut: NOT H L M
Whichever way you end up representing these relationships, make sure your arrows go in one direction
As should be clear from the chain above, the absence of H requires the absence of M (not H
not M), and - by the contrapositive - M requires H:
M H
Hope this answers your first question!
Onto your second question:
"If N is reduced, then either R is not reduced or S is not reduced."
N NOT R or NOT S
Contrapositive: R and S NOT N
(according to De Morgan's laws of propositional logic, "or" becomes "and" in the contrapositive form, and vice versa)
According to this rule, if N is reduced, it is impossible that both R and S reduced (either R or S is not reduced). Note, however, that the either/or conjunction is inclusive. In other words, it is possible that neither R nor S is reduced! The following outcomes are possible:
Nothing is reduced.
Only N is reduced.
Only R is reduced.
Only S is reduced.
Both N and R are reduced.
Both N and S are reduced.
Both R and S are reduced.
Indeed, the only possibility prohibited here is the one where all three variables are reduced.
Let me know if this clears things up!