- Wed Sep 13, 2017 6:55 pm
#39703
In this case, starting off with an odd round may have been a random choice that happened to work out. If it had not, then then next thing to do would have been to try and even-odd-even approach and see if that worked. Let's see!
First round even: J plays R and wins, S plays M and it could go either way. We have a result of either JRSML or else JRMSL.
Second round odd: R plays either M or S, no clue what happens, and L plays the other one of those two, winning and moving up to position 4. Options now are JRSLM, JSRLM, JRMLS, or JMRLS.
Third round even: J plays whoever is in second and wins, and they stay the same. L plays whoever is in third and moves up. Options are: JRLSM, JSLRM, JRLMS, or JMLRS.
We can now eliminate every one of the options that does not end with M in position 4, where it began, because that is a condition of the question. That means a final positioning of JRLMS. So, if we started with an even round and M ended up in 4th, we would have that order - JRLMS. None of our answers are possible in that case, so we have to try the Odd-Even-Odd approach that Jon shared.
Now, Jon's hypothetical was definitely intentional and informed rather than random. Why? Because we were narrowed down to two contenders (see Dave's earlier post to understand why), and we were trying to make one happen. How do you get L up from position 5 to position 2, in order to test answer C? L would have to play in all three rounds to move up three spaces, and that means he has to play in the first round, which means it's an odd round. Recognizing that that is required in order to test C out is an important, time-saving step. If you miss it, you might be casting about randomly and hoping to get lucky. However, you could still do it, as I did, and you'll still get it right.
I hope that makes sense!
First round even: J plays R and wins, S plays M and it could go either way. We have a result of either JRSML or else JRMSL.
Second round odd: R plays either M or S, no clue what happens, and L plays the other one of those two, winning and moving up to position 4. Options now are JRSLM, JSRLM, JRMLS, or JMRLS.
Third round even: J plays whoever is in second and wins, and they stay the same. L plays whoever is in third and moves up. Options are: JRLSM, JSLRM, JRLMS, or JMLRS.
We can now eliminate every one of the options that does not end with M in position 4, where it began, because that is a condition of the question. That means a final positioning of JRLMS. So, if we started with an even round and M ended up in 4th, we would have that order - JRLMS. None of our answers are possible in that case, so we have to try the Odd-Even-Odd approach that Jon shared.
Now, Jon's hypothetical was definitely intentional and informed rather than random. Why? Because we were narrowed down to two contenders (see Dave's earlier post to understand why), and we were trying to make one happen. How do you get L up from position 5 to position 2, in order to test answer C? L would have to play in all three rounds to move up three spaces, and that means he has to play in the first round, which means it's an odd round. Recognizing that that is required in order to test C out is an important, time-saving step. If you miss it, you might be casting about randomly and hoping to get lucky. However, you could still do it, as I did, and you'll still get it right.
I hope that makes sense!
Adam M. Tyson
PowerScore LSAT, GRE, ACT and SAT Instructor
Follow me on Twitter at https://twitter.com/LSATadam
PowerScore LSAT, GRE, ACT and SAT Instructor
Follow me on Twitter at https://twitter.com/LSATadam