#2 - Local, Must Be True

[Dave Killoran]

Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?f=1250&t=16333)

The correct answer choice is (C).

If S is visited fourth, then H and T are affected, since they must both be included but cannot be consecutive. thus, they must be first and third in some order:

• _H/T_ ___ _T/H_ _S_
   1 2    3      4

Now, the candidates that remain for the second visit are down to J, O, and M. But J must be visited third due to the third rule so it can be eliminated, and O cannot be visited along with S due to the second rule. thus, only M remains to be visited second:

• _H/T_ _M_ _T/H_ _S_
   1 2    3         4

Consequently, answer choice (C) must be true and is correct.


Answer choice (A): This answer cannot occur because H must be visited first or third.

Answer choice (B): This answer cannot occur because H or T must be visited third.

Answer choice (C): This is the correct answer choice.

Answer choice (D): This answer cannot occur because O cannot be visited on the same tour as S, per the second rule.

Answer choice (E): This answer choice could be true but does not have to be true since T could be visited third.