- Tue May 22, 2018 3:02 pm
#45854
Hi,
I reasoned with the above explanation by creating a venn diagram. One circle was Banjo the other Guitar. The overlapping bit was b+g. So if I had 100 = B, at least 51 is b+g. To make conclusion valid of most g not skilled in b, I need at least 52 of g only + 51 (b+g) to have 103 g. I can visually see the whole structure of the argument now. Do you think this method would work for future q's that are conditional in nature and deal with quantities?
I reasoned with the above explanation by creating a venn diagram. One circle was Banjo the other Guitar. The overlapping bit was b+g. So if I had 100 = B, at least 51 is b+g. To make conclusion valid of most g not skilled in b, I need at least 52 of g only + 51 (b+g) to have 103 g. I can visually see the whole structure of the argument now. Do you think this method would work for future q's that are conditional in nature and deal with quantities?