- Wed Jan 20, 2010 12:00 am
#41347
Setup and Rule Diagram Explanation
This is an Unbalanced: Underfunded Basic Linear game.
This game is Unbalanced: Underfunded because there are only four airlines to fill the six stops. Thus, some airlines must be used multiple times. Note also that the game does not specify that every airline is used. Thus, some viable solutions will not contain all four airlines. This makes the game much trickier. Remember, always read the rules carefully to see if every slot is filled, and if every variable must be used. In this game every slot is filled, but not every variable must be used. That creates a greater number of possible solutions.
This is an Unbalanced: Underfunded Basic Linear game.
This game is Unbalanced: Underfunded because there are only four airlines to fill the six stops. Thus, some airlines must be used multiple times. Note also that the game does not specify that every airline is used. Thus, some viable solutions will not contain all four airlines. This makes the game much trickier. Remember, always read the rules carefully to see if every slot is filled, and if every variable must be used. In this game every slot is filled, but not every variable must be used. That creates a greater number of possible solutions.
- * With the first rule, instead of drawing Not-blocks for each airline such as not LL, etc, we chose to create an
* The second and third rules can be diagrammed internally, meaning directly on the main diagram. Simply draw a double arrow between stops 1 and 6, and another arrow between stops 2 and 4.
* The fourth rule is drawn as two separate Not-blocks, but the operational effect of neither L nor M appearing before N is that if N appears in stops 2-6, then O must precede it. N can appear in stop 1 because neither L nor M would precede it.
* The last rule creates a dual-option on stop 5, and the interlaced effects of all of the rules create a limited scenario in each part of the dual-option. Thus, the last rule creates two basic templates for the game. Let us examine each.
If N is chosen for stop 5, then from the first rule N cannot be chosen for stops 4 and 6. If N cannot be chosen for stop 6, then from the second rule N cannot be chosen for stop 1. Similarly, if N cannot be chosen for stop 4, then from the third rule N cannot be chosen for stop 2. From the fourth rule we can infer that L and M cannot be chosen for stop 4, and thus O must be chosen for stop 4. When O is chosen for stop 4, from the third rule we can infer that O must be chosen for stop 2. If O is chosen for stops 2 and 4, then from the first rule O cannot be chosen for stops 1 and 3. Only L or M is then available for stop 1 (and from the second rule, stop 6 as well):
N chosen for stop 5: to represent that the same “Airline” cannot appear consecutively.
- O chosen for stop 5:
- O chosen for stop 5:
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