- PowerScore Staff
- Posts: 5972
- Joined: Mar 25, 2011
- Tue Oct 15, 2019 4:35 pm
#71209
This game is discussed in our Podcast: LSAT Podcast Episode 31: The September 2019 LSAT Logic Games Section
Complete Question Explanation
(The complete setup for this game can be found here: https://forum.powerscore.com/lsat/viewtopic.php?t=31299)
The correct answer choice is (D).
If three puppies are displayed, then we know two kittens are displayed, and thus the two kittens will be displayed first and fifth, and the three puppies will be displayed second, third, and fourth. As discussed in our setup analysis, the three puppies must come from the group of R, S, and T/W. So, to get three puppies, R and S must be selected, and then there is a choice of T or W. However, if W is selected, then G, a kitten, would have to be displayed second. That cannot occur here since the second pen is a puppy. Thus, W cannot be selected and that forces T to be selected. In order to accord with the second rule, T must then be in the third pend. Therefore, answer choice (D) is correct.
Answer choice (A): G, a kitten, can never be in the second pen in this scenario, and thus this answer choice is incorrect.
Answer choice (B): This could be true, but S could also be in the second pen so it does not have to be true.
Answer choice (C): This is essentially the same answer as (B). R and S rotate between the second and fourth pen, so this could be true, but R could also be in the second pen so it does not have to be true.
Answer choice (D): This is the correct answer choice.
Answer choice (E): W can never be displayed in this scenario, and thus this answer choice is incorrect.
Complete Question Explanation
(The complete setup for this game can be found here: https://forum.powerscore.com/lsat/viewtopic.php?t=31299)
The correct answer choice is (D).
If three puppies are displayed, then we know two kittens are displayed, and thus the two kittens will be displayed first and fifth, and the three puppies will be displayed second, third, and fourth. As discussed in our setup analysis, the three puppies must come from the group of R, S, and T/W. So, to get three puppies, R and S must be selected, and then there is a choice of T or W. However, if W is selected, then G, a kitten, would have to be displayed second. That cannot occur here since the second pen is a puppy. Thus, W cannot be selected and that forces T to be selected. In order to accord with the second rule, T must then be in the third pend. Therefore, answer choice (D) is correct.
Answer choice (A): G, a kitten, can never be in the second pen in this scenario, and thus this answer choice is incorrect.
Answer choice (B): This could be true, but S could also be in the second pen so it does not have to be true.
Answer choice (C): This is essentially the same answer as (B). R and S rotate between the second and fourth pen, so this could be true, but R could also be in the second pen so it does not have to be true.
Answer choice (D): This is the correct answer choice.
Answer choice (E): W can never be displayed in this scenario, and thus this answer choice is incorrect.
Dave Killoran
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/
