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#73606
Setup and Rule Diagram Explanation

This is an Advanced Linear, Underfunded, Unbalanced game.

Below is a basic diagram of the setup (scroll down within the picture to view the entire list of diagrammed rules). There are several points to note.

1. The linear component to the game is structured around the four consecutive weeks, which constitute the base.

2. In each week two paintings must be shown, one oil and one watercolor. Because the scenario and rules don't require a determination of which painting comes first in a given week, it is arbitrary which type of painting is placed on top and which on bottom in the diagram.

3. The game is underfunded. There are only 3 oil paintings, each of which must be shown at least once, meaning to fill the 4th week, one oil painting must be shown twice. The same is true of the watercolor paintings.

4. Since no painting can be shown in consecutive weeks, there are only a limited number of options for which weeks the paintings shown twice can be shown. They will be shown twice in weeks: 1 and 3, 2 and 4, or 1 and 4. While there isn't an efficient way to depict that in the setup (templates are not a productive option for this setup, because there are too many possible solutions), it is helpful to make the inference and keep an eye on it in any given solution.

5. Because Gold and Ping cannot be shown together, and because there must be at least one week in which H and S are shown, it cannot be the case that both Gold and Ping are shown twice (though one of them could be shown twice).

6. The final rule is a complicated "unless" form of conditional rule. Use the PowerScore "Unless Method" for diagramming unless statements. Step one is to make the "unless" clause the necessary condition. Here, "I is shown in week 1" is the necessary condition. Step two is to negate the remaining condition and then diagram it as the sufficient condition. The negation of "H cannot be shown earlier than the third week" is "H is shown earlier than the third week." In "if-then" terms the rule therefore means "If H is shown earlier than the third week (in week 1 or week 2), then I must be shown in the first week." Since I must be shown in the first week if this rule triggers, that means there is no possible scenario where H can be shown first (hence, the "Not Law" in the diagram). From the third rule, wherever H cannot be, S cannot be either, meaning we can also diagram a "Not Law" for S in week 1. Putting all the above information together, the basic takeaways from this rule are that H and S cannot be in week 1, and if H is shown in week 2, then I must be shown in week 1. The contrapositive is that if I is not shown in week 1, then H must be shown in week 3 or week 4.
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 vbkehs
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#74935
Hello! This was a tough one to practice. Can you please provide a diagram set-up with inferences?
 Jeremy Press
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#74951
Hi v,

Check out the diagram posted above, and let us know if it triggers any further questions--thanks!

Jeremy
 cleocleozuo
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#75897
Hello, thanks for the detailed explanation!
Just a clarification question: Does the "unless" condition rule applies to all Hs or just one H?
Since there are 3 spots but 4 oil elements, we could potentially have 2Hs or 2Is. In this case, do we know if this conditional rule applies to all Hs and Is? Or will IHIG combination work? (eg: H is in position 2 which triggers the rule and puts I in position 1. Can there be another I in position 3 or 4?)
 Adam Tyson
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#75982
Keep in mind, cleocleozuo, that there is just one H. It's still just one painting, even though it could be shown twice! That rule is telling us that H cannot be shown at all before week 3 unless I is shown in week 1, so even if H is shown twice it could only be in weeks 2 and 4 (two non-consecutive weeks, with I in week 1 and G in week 3). There would be no way to put an H in week 1, because that would violate that conditional rule.

Your idea of I showing in weeks 1 and 3 looks entirely possible! S would have to be shown in week 2 with H (because otherwise we could not have S in the game at all), R would have to be shown in week 4 with G (because G cannot be paired with either P or S), and P would have to be shown in week 3 with I (because S cannot be with I and we cannot have R twice in a row). The only thing left uncertain in that case would be the Watercolor in week 1 - it could be P or R.

Good work!
 cleocleozuo
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#76183
Thank you for the detailed explanation!
 ncolicci11
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#77900
Is inference G -> R valid? However, R can be placed with over variables?
 cmorris32
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#78057
ncolicci11 wrote:Is inference G -> R valid? However, R can be placed with over variables?
ncolicci11, not sure if this helps, but I spent a lot of time working through this game and I also made the G :arrow: R inference. We know that G is an oil painting, which means that it must be shown with a watercolor painting. G cannot be shown with P because of the not-law. G cannot be shown with S because S requires oil painting H. Therefore, any time that G is shown in a given week, the watercolor that is shown must be R.

However, if R is shown in a given week, we do not necessarily know that G is shown that week. We know this because, although a sufficient condition cannot occur without a necessary condition, a necessary condition can occur on its own without the sufficient condition. So R can be shown in a given week with I or H.

(Also, question #17 of this game is a rule substitution question, which I think restates this inference to show that G requires R.)
 j199393
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#79279
What is the correct way of diagramming this rule?

Hanbok must be shown in any week in which Sails is shown.

I was having trouble finding out if it should be H --> H OR S--> S
S H

Thank you!
 j199393
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#79282
Sorry, when I tried to align that rule it didn't appear correctly. Is it H --> H/S (H/S = H and S in the same week) or S--> S/H?

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