- Thu Jun 28, 2018 1:43 pm
#47138
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=2909)
The correct answer choice is (B)
The question stem kindly provides the complete color combination in one of the windows—P, R, and O—and then asks you to identify a complete color combination that could be used in another window. The initial setup appears as follows, with no window numbers specified:
Of course, the first rule specifies that one of the windows must have G and P, and so that fact can be added to the diagram:
Y must also be used in one of the windows, and from the third rule Y cannot be used with G or O, and so Y must be used in the remaining window, along with P:
With the diagram above—which shows the minimum color usage in the other two windows—answer choices (C), (D), and (E) can each be eliminated. This is because each contains exactly two colors, and any two color window in under the above scenario would have to be GP or YP. As neither of those color combinations is listed in any of those three answers, each can be eliminated.
Answer choice (A) can also be eliminated because it does not contain P, and the diagram shows that each window must contain P. Thus, answer choice (B) is the correct answer, and under answer choice (B), the “third” window would have the remaining R:
(The complete setup for this game can be found here: lsat/viewtopic.php?t=2909)
The correct answer choice is (B)
The question stem kindly provides the complete color combination in one of the windows—P, R, and O—and then asks you to identify a complete color combination that could be used in another window. The initial setup appears as follows, with no window numbers specified:
Of course, the first rule specifies that one of the windows must have G and P, and so that fact can be added to the diagram:
Y must also be used in one of the windows, and from the third rule Y cannot be used with G or O, and so Y must be used in the remaining window, along with P:
With the diagram above—which shows the minimum color usage in the other two windows—answer choices (C), (D), and (E) can each be eliminated. This is because each contains exactly two colors, and any two color window in under the above scenario would have to be GP or YP. As neither of those color combinations is listed in any of those three answers, each can be eliminated.
Answer choice (A) can also be eliminated because it does not contain P, and the diagram shows that each window must contain P. Thus, answer choice (B) is the correct answer, and under answer choice (B), the “third” window would have the remaining R:
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