#13- Local, Must Be True

[Dave Killoran]

Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=1452)

The correct answer choice is (D)

If T is not included in the display, then the available pool for the mauve dinosaurs is L/U and V. However, since V must then be included, from the fifth rule U cannot be included, and thus L must be the other mauve dinosaur. This information is sufficient to answer the question, as a mauve U cannot be included in the display. Answer choice (D) is thus correct.

However, for academic purposes, let us continue on with the analysis, as the entire set of displayed toys can be determined. With T and U eliminated, the remaining five dinosaurs—I, L, P, S, and V must be displayed:

Jun 09__M12_game#3_L11_explanations_game#3_#13_diagram_1.png

This diagram confirms that the other four answer choices must each occur.

[cpassaro]

I'm lost on this game and I feel like I'm missing an inference. With a lot of time and effort, I was able to answer #12, 13 and 16 correctly, but I'm stumped on the others.

Could you please explain them?

Thanks

[Jon Denning]

Hey cpassaro - thanks for the questions. First, it will be helpful to refer to this previous post regarding the setup: lsat/viewtopic.php?f=156&t=1452.

The question stem eliminates T from the display. That leaves the choices of L/U and V for the mauve dinosaurs. But, when V is selected, then U cannot be, and so the two mauve dinosaurs are V and L:

D: S V L __ __
C: R M M __ __

At this point, you know that D cannot occur and must therefore be the correct answer.

Thanks!

Jon

[cpassaro]

Thanks! Phew. Glad I asked.