- Sat Jan 21, 2012 12:00 am
#25090
Setup and Rule Diagram Explanation
This is a Grouping: Defined-Fixed, Unbalanced: Overloaded game.
The game scenario establishes that five candidates are available for three ambassadorships:
J K L N O5
Because there is only one available ambassadorship for each country (for a total of 3 ambassadorships) and five candidates total, this game is Unbalanced: Overloaded (5 into 3). Let us examine each rule:
First Rule:
The first rule establishes that at exactly one of K and N is assigned an ambassadorship:
Consequently, if any one of J, L, or O is removed from consideration, the other two must be assigned ambassadorships. Understanding this relationship makes the game considerably easier.
Second Rule:
The second rule is a simple conditional rule, and can be diagrammed as:
The first and second rules can be combined easily, but we will address that connection after examining each of the four rules individually.
Third Rule:
The third rule is the first to specify a country, and it establishes that O cannot be assigned to Venezuela while K is assigned to Yemen:
Fourth Rule:
The fourth rule indicates that if L is assigned an ambassadorship, it must be to Zambia:
With the four rules diagrammed, let’s take a moment to consider the inferences produced by combining the rules.
First and Second Rules Combined:
The first and second rules are naturally connected through K:
First and Fourth Rules Combined:
The fourth rule, as mentioned previously, plays a significant role in this game. Because there are a limited number of “extra” candidates for the three ambassadorships, and because L is restricted to being assigned only to Zambia, if other variables are assigned to Zambia, further restrictions ensue. Specifically, consider what occurs when K or N is assigned to Zambia, because the assignment of either K or N eliminates the other variable from the candidate pool.
Continuing on in this vein, because the fourth rule is so restrictive, let us examine what occurs when the remaining two variables—J and O—are assigned to Zambia.
Combining the previous information produces the final setup for this game:
J K L N O5
Inferences:
This is a Grouping: Defined-Fixed, Unbalanced: Overloaded game.
The game scenario establishes that five candidates are available for three ambassadorships:
J K L N O5
Because there is only one available ambassadorship for each country (for a total of 3 ambassadorships) and five candidates total, this game is Unbalanced: Overloaded (5 into 3). Let us examine each rule:
First Rule:
The first rule establishes that at exactly one of K and N is assigned an ambassadorship:
- K/N 1
- K N
- K/N, J, L, O
Consequently, if any one of J, L, or O is removed from consideration, the other two must be assigned ambassadorships. Understanding this relationship makes the game considerably easier.
Second Rule:
The second rule is a simple conditional rule, and can be diagrammed as:
- J K
- [ K J ] L, N, O
The first and second rules can be combined easily, but we will address that connection after examining each of the four rules individually.
Third Rule:
The third rule is the first to specify a country, and it establishes that O cannot be assigned to Venezuela while K is assigned to Yemen:
- OV KY
Fourth Rule:
The fourth rule indicates that if L is assigned an ambassadorship, it must be to Zambia:
- L LZ
With the four rules diagrammed, let’s take a moment to consider the inferences produced by combining the rules.
First and Second Rules Combined:
The first and second rules are naturally connected through K:
- J K N
- J N
First and Fourth Rules Combined:
The fourth rule, as mentioned previously, plays a significant role in this game. Because there are a limited number of “extra” candidates for the three ambassadorships, and because L is restricted to being assigned only to Zambia, if other variables are assigned to Zambia, further restrictions ensue. Specifically, consider what occurs when K or N is assigned to Zambia, because the assignment of either K or N eliminates the other variable from the candidate pool.
- When K is assigned to Zambia:
When K is assigned to Zambia, from the first rule N cannot be assigned an ambassadorship, and from the fourth rule L cannot be assigned to Zambia, and thus L cannot be assigned an ambassadorship. Thus, when K is assigned to Zambia, N and L cannot be assigned ambassadorships, and J and O must be assigned ambassadorships:
- KZ N + L = KZ, J, O
When N is assigned to Zambia, from the first rule K cannot be assigned an ambassadorship, and from the fourth rule L cannot be assigned to Zambia, and thus L cannot be assigned an ambassadorship. But, with K removed from the candidate pool, from the second rule we can infer that J cannot be assigned an ambassadorship, leading to a situation where J, K, and L are no longer in the candidate pool. Because there must be three ambassadors, this situation produces an invalid result, leading to the inference that N cannot be assigned to Zambia:
- NZ
Continuing on in this vein, because the fourth rule is so restrictive, let us examine what occurs when the remaining two variables—J and O—are assigned to Zambia.
- When J is assigned to Zambia:
- When J is assigned to Zambia, from the second rule K must be assigned an ambassadorship, and from the fourth rule L cannot be assigned to Zambia, and thus L cannot be assigned an ambassadorship. Additionally, from the first inference, N cannot be assigned an ambassadorship, meaning that the three ambassadorships must be assigned to J, K, and O.
With J is assigned to Zambia, K and O must be assigned to Venezuela and Yemen. But, K and O both figure in the third rule, and applying that rule we can infer that K must be assigned to Venezuela and O must be assigned to Yemen:
- Thus:
- JZ KV, OY, JZ
- When O is assigned to Zambia:
- When O is assigned to Zambia, from the fourth rule L cannot be assigned to Zambia, and thus L cannot be assigned an ambassadorship. This leaves J, K, and N in the selection pool. But, from the contrapositive of the second rule, because the removal of K would also remove J from the pool (and thus leave an insufficient number of candidates), K must be in the pool. Applying the first rule, N therefore cannot be in the pool, and the candidate pool must be J, K, and O. There are no restrictions on the placement of J and K at that point:
- Thus:
- OZ JV/Y, KY/V, OZ
Combining the previous information produces the final setup for this game:
J K L N O5
Inferences:
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