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- Thu Jun 14, 2018 2:39 pm
#46595
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=6851)
The correct answer choice is (A)
Because this question asks for the answer choice which could be false (i.e., is not necessarily true), the answer choices which must be true can be ruled out.
The initial condition in the question stem produces the following setup:
This condition leaves only habitats 1, 2, 4, and 5, available for the remaining reptiles. the second condition in the question stem establishes that no snake is housed in a habitat next to another snake. Because there are four snakes, and the maximum number of reptiles housed in a habitat is two, we can infer that two of the snakes are housed in habitat 1 or 2, and the other two snakes are housed in habitat 4 or 5:
Answer choice (A) is the correct answer choice because none of the rules would preclude the placement of snakes in one or both remaining odd numbered habitats.
Answer choice (B) is incorrect, because it must be true that there are no male lizards—if there were any, they would be forced to be next to female snakes, which is not allowed.
Answer choices (C) and (E) must be true based on the numerical distributions in this game. There are four snakes and three lizards, with only four habitats to hold them. Since lizards and snakes cannot be housed together, the distribution must be as follows: two habitats with two snakes each, one with two lizards, and one with one lizard.
Answer choice (D) is incorrect, because if the snakes must be separated, each snake habitat must be next to a lizard habitat. Therefore it must be the case that the lizard habitats are not next to one another. Since it must be true, answer choice (D) is incorrect.
(The complete setup for this game can be found here: lsat/viewtopic.php?t=6851)
The correct answer choice is (A)
Because this question asks for the answer choice which could be false (i.e., is not necessarily true), the answer choices which must be true can be ruled out.
The initial condition in the question stem produces the following setup:
This condition leaves only habitats 1, 2, 4, and 5, available for the remaining reptiles. the second condition in the question stem establishes that no snake is housed in a habitat next to another snake. Because there are four snakes, and the maximum number of reptiles housed in a habitat is two, we can infer that two of the snakes are housed in habitat 1 or 2, and the other two snakes are housed in habitat 4 or 5:
Answer choice (A) is the correct answer choice because none of the rules would preclude the placement of snakes in one or both remaining odd numbered habitats.
Answer choice (B) is incorrect, because it must be true that there are no male lizards—if there were any, they would be forced to be next to female snakes, which is not allowed.
Answer choices (C) and (E) must be true based on the numerical distributions in this game. There are four snakes and three lizards, with only four habitats to hold them. Since lizards and snakes cannot be housed together, the distribution must be as follows: two habitats with two snakes each, one with two lizards, and one with one lizard.
Answer choice (D) is incorrect, because if the snakes must be separated, each snake habitat must be next to a lizard habitat. Therefore it must be the case that the lizard habitats are not next to one another. Since it must be true, answer choice (D) is incorrect.
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Dave Killoran
PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
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PowerScore Test Preparation
Follow me on X/Twitter at http://twitter.com/DaveKilloran
My LSAT Articles: http://blog.powerscore.com/lsat/author/dave-killoran
PowerScore Podcast: http://www.powerscore.com/lsat/podcast/
