#19 - Local, Must Be True

[Dave Killoran]

Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?f=182&p=88548#p88548)

The correct answer choice is (A).

This question is simply a test of whether you can diagram the first rule correctly.

From the first rule, F G K is known to be true. Thus, if F’s delivery is fourth, G’s must be fifth, and K’s must be sixth. Consequently, answer choice (A) must be true and is correct.

[cgleeson]

Hi,

Quick question...how is B incorrect? I see how A works, however if G is 4th, H would have to be 2nd?


M ->H ->L->F->G->K
even if M came after K there is no way to correctly diagram it showing F as the 4th delivery.

BTW this is a really cool game

[katehos]

Hi Chris!

H does not have to be delivered second even when F is delivered 4th, since you could create the order of:

M -> L -> H -> F -> G -> K

This order does not violate any of the rules in the stimulus and H is listed 3rd, not 2nd! The main rule at play for showing how this specific example is valid is the third rule (since we've already placed F, G, and K in spots 4-6 according to the local condition and the first rule), which can be diagrammed as:

F M L H (contrapositive being H L M F)

As you can see, neither sufficient condition of the above diagram is invoked by this placement of variables, so it is not a violation of any of the rules nor the local condition and thus (B) does not have to be true!

I hope this helps
Kate

P.S. I agree that this is a very cool game!