LSAT and Law School Admissions Forum

Get expert LSAT preparation and law school admissions advice from PowerScore Test Preparation.

 Administrator
PowerScore Staff
  • PowerScore Staff
  • Posts: 8950
  • Joined: Feb 02, 2011
|
#38536
Complete Question Explanation
(The complete setup for this game can be found here: lsat/viewtopic.php?t=12828)

The correct answer choice is (D)

If Lifestyle has photographs by G and H, we need to use Template 2 to construct our local diagram:
PT76_O15 LG Explanations_Game #2_#9_diagram 1.png
Note that since Lifestyle and Metro must have at least one photographer in common, Metro must now have either G or H.

Answer choice (A) is incorrect, because it is possible that Metro contains no photographs by F.

Answer choices (B) and (C) are incorrect, because Metro can have anywhere from 0 to 2 photographs by G.

Answer choice (D) is the correct answer choice, as shown in the local diagram above. Since the number of photographs in Lifestyle by H must match the number of photographs in Sports by F, F must have exactly one photograph in Sports. And, since G cannot have any photographs in Sports (last rule), it follows that the other photograph in Sports is by H.

Answer choice (E) cannot be true, because one of the photographs in Sports must be by F.
You do not have the required permissions to view the files attached to this post.
 carmenp
  • Posts: 1
  • Joined: Jul 28, 2021
|
#89138
Hi,

I see why A and E are incorrect, but I am having trouble understanding why D is correct. With this being a "must be true" question, isn't it also possible that both spots in the sports section could be F? (And this to me seems like the reasoning that is used to rule out B and C). Why in this specific case would H have to fill the remaining spot?

Any help would be much appreciated, thank you!
 Robert Carroll
PowerScore Staff
  • PowerScore Staff
  • Posts: 1819
  • Joined: Dec 06, 2013
|
#89166
carmen,

The third rule requires the number of H photographs in L to be equal to the number of F photographs in S. Because the local condition of the question stipulates that the number of H photographs in L will be 1, we cannot have 2 F's in S, but can only have one. G is never in S, so the remaining S space is H.

Robert Carroll

Get the most out of your LSAT Prep Plus subscription.

Analyze and track your performance with our Testing and Analytics Package.