- Tue Dec 20, 2016 12:00 am
#41105
Setup and Rule Diagram Explanation
This is a Defined-Moving, Balanced, Numerical Distributions Grouping game.
The game requires us to assign six variables (teaching assistants) to three different groups (courses). Since each variable is used exactly once, the game is Balanced. However, only one of the groups (Markets) requires a specific number of variables (2), making this game Defined-Moving.
With all the rules represented, your initial setup should look like this:
A thorough analysis of this game requires understanding the Numerical Distributions that govern the assignment of variables to groups. Since there must be exactly two variables assigned to Markets, there are three fixed distributions at play: 2-2-2, 1-2-3, and 3-2-1. Fixed distributions usually, though not always, present an opportunity to undertake a templates-based approach, where each distribution provides the basis for a different template. Unfortunately, in this game, the rules do not seem powerful enough to justify such an approach.
In theory, a templates-based approach is also possible by tracing the placement of the ST block in each group. However, the block is not exclusive, i.e. it allows for the inclusion of other variables in the same group as S and T. Furthermore, none of the other variables are directly restricted by the placement of the ST block. A templates approach based on the placement of the ST block is a risky proposition, and is probably not worth the investment of time.
A better course of action would be to analyze the last rule, which is complicated enough to warrant a closer look:
Since Y and Z must both be assigned to P if either one of them is, we are looking at a bi-conditional statement: if Y is assigned to P, then Z must also be assigned to P. Inversely, if Z is assigned to P, then Y must follow suit. By the contrapositive, if either Y or Z is not assigned to P, the other variable cannot be assigned to P either:
Essentially, the rule entails two situations that are both mutually exclusive and collectively exhaustive: either Y and Z are both assigned to P, or else neither Y nor Z is assigned to P. We can represent the implication of this rule using two possible outcomes, as shown below:
Although neither scenario is sufficiently restrictive to place all, or even most, of the variables (and thus a strictly-templates attack is unwise), an early consideration of this duality may obviate to some degree the need to apply the complex language of the last rule to each and every question. Effectively the game is “split,” and the full implication of the last rule can be more clearly seen with this quick examination.
Observant test takers will also notice that Possibility 1 is the more restrictive of the two, since the ST block cannot be assigned to P (because the maximum number of variables per group is 3). Therefore, in that option the ST block must be assigned to either L or M, and this new split is also worth a look:
Note that in 1B, V must be assigned to L, because Y and V cannot be assigned to the same group as each other (third rule), and M is full. Unfortunately, as noted, Possibility 2 is not nearly as restricted, because Y and Z can be assigned to either of the two remaining groups, whether separately or together. Thus it remains too open-ended to merit further analysis, and can be left alone.
This is a Defined-Moving, Balanced, Numerical Distributions Grouping game.
The game requires us to assign six variables (teaching assistants) to three different groups (courses). Since each variable is used exactly once, the game is Balanced. However, only one of the groups (Markets) requires a specific number of variables (2), making this game Defined-Moving.
With all the rules represented, your initial setup should look like this:
A thorough analysis of this game requires understanding the Numerical Distributions that govern the assignment of variables to groups. Since there must be exactly two variables assigned to Markets, there are three fixed distributions at play: 2-2-2, 1-2-3, and 3-2-1. Fixed distributions usually, though not always, present an opportunity to undertake a templates-based approach, where each distribution provides the basis for a different template. Unfortunately, in this game, the rules do not seem powerful enough to justify such an approach.
In theory, a templates-based approach is also possible by tracing the placement of the ST block in each group. However, the block is not exclusive, i.e. it allows for the inclusion of other variables in the same group as S and T. Furthermore, none of the other variables are directly restricted by the placement of the ST block. A templates approach based on the placement of the ST block is a risky proposition, and is probably not worth the investment of time.
A better course of action would be to analyze the last rule, which is complicated enough to warrant a closer look:
Since Y and Z must both be assigned to P if either one of them is, we are looking at a bi-conditional statement: if Y is assigned to P, then Z must also be assigned to P. Inversely, if Z is assigned to P, then Y must follow suit. By the contrapositive, if either Y or Z is not assigned to P, the other variable cannot be assigned to P either:
Essentially, the rule entails two situations that are both mutually exclusive and collectively exhaustive: either Y and Z are both assigned to P, or else neither Y nor Z is assigned to P. We can represent the implication of this rule using two possible outcomes, as shown below:
Although neither scenario is sufficiently restrictive to place all, or even most, of the variables (and thus a strictly-templates attack is unwise), an early consideration of this duality may obviate to some degree the need to apply the complex language of the last rule to each and every question. Effectively the game is “split,” and the full implication of the last rule can be more clearly seen with this quick examination.
Observant test takers will also notice that Possibility 1 is the more restrictive of the two, since the ST block cannot be assigned to P (because the maximum number of variables per group is 3). Therefore, in that option the ST block must be assigned to either L or M, and this new split is also worth a look:
Note that in 1B, V must be assigned to L, because Y and V cannot be assigned to the same group as each other (third rule), and M is full. Unfortunately, as noted, Possibility 2 is not nearly as restricted, because Y and Z can be assigned to either of the two remaining groups, whether separately or together. Thus it remains too open-ended to merit further analysis, and can be left alone.
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