Setup and Rule Diagrams

[oommenj2]

Hi, can you please go through how you got the answer for number 1

[Adam Tyson]

Hey there, oommenj2! You'll find a brief description of the process of elimination that leads to the correct answer to #1 for this game in this thread:

https://forum.powerscore.com/lsat/viewtopic.php?t=15735

To expand on that description, just think about where the "KO/OK" block would be placed in the setup if two variables, neither of which was K or O, were both on Tuesday. If that happened, either K or O would be forced to go on Thursday, with I, and then you would have two days that had two students each, a violation of the requirements set forth in the scenario.

Check out that description, play with it a little bit, and follow up in that thread if you need more help with it!

[momgoingbacktoschool]

Setup and Rule Diagram Explanation

This is a Basic Linear: Unbalanced: Overloaded game.

J93_Game_#1_setup_diagram 1.png

This setup has been created vertically to make it easier to show that Monday and Wednesday have only one student. The bar at the end of the slots on each of those days signifies that only one student can be assigned to each day.

This game is Unbalanced: Overloaded because there are six students but only five available days. The game scenario establishes that all five days are used and that all students are tutored, and that one of the days receives two students. Thus, there is a 2-1-1-1-1 numerical distribution of students to the days, where the instructor coaches one student every day, except for one of the days where the instructor coaches two students. Although this distribution is in general quite manageable, this game turns out to be difficult.

The fourth rule establishes that neither Monday nor Wednesday can be the day with two students, and thus either Tuesday, Thursday, or Friday has two students. Within this group of three, Thursday is the most restricted because the addition of one more variable satisfies the two students-on-one-day rule. Thus, Monday, Wednesday, and Thursday should be scrutinized closely in this game because the assignment of any available student to one of those days “closes off” that day to further students.

Note that one approach to this game would be to quickly sketch out all three scenarios—one where Tuesday is assigned two students, one where Thursday is assigned two students, and one where Friday is assigned two students.

The first rule creates an H Z sequence. Because Monday can be assigned only one student, a Z Not Law is created on Monday. However, because Friday can be assigned two students, no Not for H can be created on Friday, although Friday is the only day on which both H and Z could possibly be coached by the instructor.

The third rule creates a rotating block between K and O. While this block initially appears unimportant, note that the block action in combination with the limitation of only one day having two students creates certain inferences involving K and O. For example, if two students are assigned to Tuesday, that pair must include either K or O (if Tuesday did not have K or O, then K or O would have to go on Thursday, but this would violate the rule about exactly one day being assigned two students).

Shouldn't there be not K and not O next to Friday on the initial diagram?

[momgoingbacktoschool]

Setup and Rule Diagram Explanation

This is a Basic Linear: Unbalanced: Overloaded game.

J93_Game_#1_setup_diagram 1.png

This setup has been created vertically to make it easier to show that Monday and Wednesday have only one student. The bar at the end of the slots on each of those days signifies that only one student can be assigned to each day.

This game is Unbalanced: Overloaded because there are six students but only five available days. The game scenario establishes that all five days are used and that all students are tutored, and that one of the days receives two students. Thus, there is a 2-1-1-1-1 numerical distribution of students to the days, where the instructor coaches one student every day, except for one of the days where the instructor coaches two students. Although this distribution is in general quite manageable, this game turns out to be difficult.

The fourth rule establishes that neither Monday nor Wednesday can be the day with two students, and thus either Tuesday, Thursday, or Friday has two students. Within this group of three, Thursday is the most restricted because the addition of one more variable satisfies the two students-on-one-day rule. Thus, Monday, Wednesday, and Thursday should be scrutinized closely in this game because the assignment of any available student to one of those days “closes off” that day to further students.

Note that one approach to this game would be to quickly sketch out all three scenarios—one where Tuesday is assigned two students, one where Thursday is assigned two students, and one where Friday is assigned two students.

The first rule creates an H Z sequence. Because Monday can be assigned only one student, a Z Not Law is created on Monday. However, because Friday can be assigned two students, no Not for H can be created on Friday, although Friday is the only day on which both H and Z could possibly be coached by the instructor.

The third rule creates a rotating block between K and O. While this block initially appears unimportant, note that the block action in combination with the limitation of only one day having two students creates certain inferences involving K and O. For example, if two students are assigned to Tuesday, that pair must include either K or O (if Tuesday did not have K or O, then K or O would have to go on Thursday, but this would violate the rule about exactly one day being assigned two students).

Shouldn't there be not K and not O next to Friday on the initial diagram?

nevermind. since 2 students can go on Thursday then it is possible for K or O to go on Friday.

[lauratenorio]

Couldn't you put Z in tuesday and wouldn't that have the same effect? the rules don't say you can't put two on tuesday

[Adam Tyson]

Which question are you referring to, lauratenorio? Yes, Tuesday can be the day that has two students scheduled, with every other day having just one student. If Z was on Tuesday, H would have to be on Monday. Then the OK block could be Tuesday and Wednesday, or Wednesday and Thursday, or Thursday and Friday. U would then take whichever day did not yet have something (Wednesday or Friday).