Setup and Rule Diagrams

[Basia W]

Good morning,

Thank you for such a thorough diagram of the set-up! I had one question regarding how you linked P-G. I understand the chain of P S9 NOT W, but then you link it to G even though W is not negative. Can you link P G:dblline: Not W?

Thank you for your clarification!

Best,

Basia

[Nikki Siclunov]

Hi Basia,

Thanks for your question. Let's analyze the relevant rule a bit more closely:

She must take either G or W, but cannot take both.

There are two parts to this rule:

1. She must take either G or W, i.e. if she doesn't take G, she must take W (and vice versa). We can represent this conditionally in the following manner:

NOT G W
NOT W G

2. ... but cannot take both. In other words, if she takes one of them, she cannot take the other:

G NOT W
W NOT G

When we combine these two rules, we arrive at the following conditional representation:

NOT G W
NOT W G

Consequently, the rule can be combined with the P S9 NOT W chain, allowing us to make the inference that P G.

Hope this helps! Let me know.

[srcline@noctrl.edu]

Hello,

So I understood Nikki's earlier explanation on the fact that R or J or both can be selected and G or W can be selected but not both because of the stipulation in the rule. However, I think I maybe making some unwarranted inferences because I had J M and M R and WH S9am.

Thankyou
Sarah

[queenbee]

Hi
Question for you regarding the set up.

If !R -- > J
and the contra
If !J --> R

In this particular case, could both J and R be selected? Meaning, if J is selected, it has no impact on if R is selected?
I am guessing that this is not an option due to the nature of the game?

Thank you!

[Adam Tyson]

I see no problem with selected both J and R, queenbee, as neither of those choices precludes the other. Her four courses would be J, R, exactly one of either G or W, and one of the two S options. She could not take either M or P - M is out because she is taking J, and P is out because it would also bring in S9, making for a total of 5 courses.