- Mon Aug 10, 2020 1:08 am
#77865
Thank you, Powerscore for being here everyday with me...
I believe that I understand the core of the argument, and also the reason why most of people are struggling with it. Please allow me to post my train of thinking regarding this question, and please critic me to help me get better.
The core principle here is really simple, and could be explained as -
The degree of feeling easier to put the product together of (Most customer / instruction available ) > The degree of feeling easier to put the product together of ( Most customer / Instruction unavailable )
In maths-wise, principle could be written as D( C/ IA ) > D ( C / IUA ), IA = ~ UIA, and ( C/ IA ) + ( C / IUA ) = MC
D = The degree of feeling easier to put the product together, ( C / IA ) = (Most customer / instruction available ), ( C / IUA ) = ( Most customer / Instruction unavailable ), and MC = Most of the customer.
The question apparently wants us to find if there is any case that this principle can't " always " follow as in the way that if under any circumstances, D( C/ IA ) < D ( C/ IUA ) or D( C/IA ) = D ( C/ IUA )
A. Unfortunately, we can not infer anything from this answer due to the subject discussed are totally different. In answer A, we are discussing Customer who " assemble product " , and apparently, we know both C/IA and C/ IUA all resemble the products. So, It is actually possible that regardless great difficulty exists, D( C/IA ) still permanently > D ( C/ IUA ). Definitely we are not eliminating the answer because of the varied subject discussed, but of the core of the answer fail to explicitly point out if D ( C/IA ) < or = ( C/ IUA ) would ever happened.
B. Just as the reason to eliminate A, the same applies to B as well.
C. Regardless of the subject discussed " seems " to be different; however, If the total number customer who assemble the product = {( C / IA ) + ( C / IUA ) } who assemble the product, then we are really discussing the same groups of customers, and It says that " most of the total number customers, without instructions, all feel very easy to assemble the product, then if the total number of the customer is 10, and most of the customer without instructions all feel very easy, then Could it be true that D ( C/IA ) < D ( C / IUA ) ? Yes ! as long as C/IUA > 6, and fortunately, C/IUA would never equal 50 due to the quantifier, most.
D. Tricky Tricky. ( C/ IA ) who assemble product has no difficulty. Ok, but it does not mean that D( C/IA ) would ever < or = ( C/ IUA )
E. Some of C will be ( C / IA ) only when they have difficulty. OK, but it does not mean that D ( C / IA ) would ever < or = D ( C / IUA ).
I might be wrong within my train of thoughts; however, I extremely enjoy employing math skills to crack some questions of LR and LG.
Hope this help, and Please let me know if I can offer any support.